SSC CGL Maths Syllabus (साथ ही मैथ्स के सर्वश्रेष्ठ फ्री नोट्स डाउनलोड करे)

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SSC CGL Maths Syllabus (साथ ही मैथ्स के सर्वश्रेष्ठ फ्री नोट्स डाउनलोड करे)

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SSC CGL Syllabus 2022:Quantative Aptitude (Mathematics)-

SSC CGL Maths Syllabus for SSC CGL Tier 1: Quantitative Aptitude questions are designed to test the ability of the candidates to use numbers and number appropriately. Following are the topics of SSC CGL Mathematics Syllabus:

counting whole numbers,
slave number,
relationship between fractions and numbers,
Profit and Loss,
Time and Distance,
time and work,
Percent
Ratio and Proportion,
Discount
Partnerships,
mixing and separation,
square root,
average,
graph of linear equations,
Triangle and its different types,
similarity in triangles,
Interest,
Basic Arithmetic and Elementary Variation,
circle and its chord,
triangle,
quadrilateral,
tangent line,
The angle subtended by the chord of the circle,
common tangent of two or more circles,
even polygon,
Circle,
long prism,
long circular cone,
long circular cylinder,
Circle,
height and distance
hemisphere,
rectangular parallelepiped,
Vertical Pyramid of Triangular and Square Base
histogram,
frequency polygon,
bar diagram and pie-chart,
trigonometric ratio,
degree and radian measure, identity,
complementary angle

SSC CGL Maths Questions with Solutions PDF

1. Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:

(a) broke even, (b) lost 4 cents, (c) gained 4 cents, (d) lost 10 cents, (e) gained 10 cents

Solution:

Selling price of the first pipe = $1.20

Profit = 20%

Let’s try to find the cost price of the first pipe

CP = Selling price – Profit

CP = 1.20 – 20% of CP

CP = 1.20 – 0.20CP

CP + 0.20CP = 1.20

1.20CP = 1.20

CP = 1.201.20
CP = $ 1

Selling price of the Second pipe = $1.20

Loss = 20%

Let’s try to find the cost price of the second pipe

CP = Selling price + Loss

CP = 1.20 + 20% of CP

CP = 1.20 + 0.20CP

CP – 0.20CP = 1.20

0.80CP = 1.20

CP = 1.200.80
CP = $1.50

Therefore, total cost price of the two pipes = $1.00 + $1.50 = $2.50

And total selling price of the two pipes = $1.20 + $1.20 = $2.40

Loss = $2.50 – $2.40 = $0.10

Therefore, Mr. Jones loss 10 cents.

Answer: (d)

2. The distance light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 100 years is:

(a) 587 × 108 miles, (b) 587 × 1010 miles, (c) 587 × 10-10 miles, (d) 587 × 1012 miles, (e) 587 × 10-12 miles

Solution:

The distance of the light travels in 100 years is:

5,870,000,000,000 × 100 miles.

= 587,000,000,000,000 miles.

= 587 × 1012 miles.

Answer: (d)

3. What is |-26|?

(a) -26,

(b) 26,

(d) 1

Solution:

|-26|

= 26.

Answer: (b)

4. Multiply: (x – 4)(x + 5)

(a) x2 + 5x – 20,

(b) x2 – 4x – 20,

(d) x2 + x – 20.

Solution:

(x – 4)(x + 5).

= x(x + 5) -4(x + 5).

= x2 + 5x – 4x – 20.

= x2 + x – 20.

Answer: (d)

SSC CGL Maths Syllabus (साथ ही मैथ्स के सर्वश्रेष्ठ फ्री नोट्स डाउनलोड करे)

5. Factor: 5×2 – 15x – 20.

(a) 5(x-4)(x+1),

(b) -2(x-4)(x+5),

(d) 5(x+4)(x+1).

Solution:

5×2 – 15x – 20.

= 5(x2 – 3x – 4).

= 5(x2 – 4x + x – 4).

= 5{x(x – 4) +1(x – 4)}.

= 5(x-4)(x+1).

Answer: (a).

6. If 102y = 25, then 10-y equals:

(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5

Solution:

102y = 25

(10y)2 = 52

10y = 5

1/10y = 1/5

10-y = 1/5

Answer: (e)

7. The value of x + x(xx) when x = 2 is:

(a) 10, (b) 16, (c) 18, (d) 36, (e) 64

Solution:

x + x(xx)

Put the value of x = 2 in the above expression we get,

2 + 2(22)

= 2 + 2(2 × 2)

= 2 + 2(4)

= 2 + 8

= 10

Answer: (a)

8. The sum of three numbers is 98. The ratio of the first to the second is ²/₃, and the ratio of the second to the third is ⁵/₈. The second number is:

(a) 15, (b) 20, (c) 30, (d) 32, (e) 33

Solution:

Let the three numbers be x, y and z. (SSC CGL Maths Syllabus)

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is ²/₃.

x/y = ²/₃.

x = ²/₃ × y.

x = ^2y/₃.

The ratio of the second to the third is ⁵/₈.

^y/_z = ⁵/₈.

^z/_y = ⁸/₅.

z = ⁸/₅ × y.

z = ^8y/₅.

Put the value of x = ^2y/₃ and z = ^8y/₅ in (i).

^2y/₃ + y + ^8y/₅ = 98

^49y/₁₅ = 98.

49y = 98 × 15.

49y = 1470.

y = ¹⁴⁷⁰/₄₉.

y = 30 .

Therefore, the second number is 30. (SSC CGL Maths Syllabus)

Answer: (c)

Also Check PDF:-

Important Maths Questions for SSC CGL Exam

1. Which is greater than 4?

(a) 5,

(b) -5, (SSC CGL Maths Syllabus)

(d) -25.

Solution:

5 greater than 4.

Answer: (a)

2. Which is the smallest?

(a) -1,

(b) -1/2,

(d) 3.

Solution:

The smallest number is -1.

Answer: (a)

(SSC CGL Maths Syllabus)

3. Combine terms: 12a + 26b -4b – 16a.

(a) 4a + 22b,

(b) -28a + 30b,

(d) 28a + 30b.

(SSC CGL Maths Syllabus)

Solution:

12a + 26b -4b – 16a.

= 12a – 16a + 26b – 4b.

= -4a + 22b.

Answer: (c)

4. Simplify: (4 – 5) – (13 – 18 + 2).

(a) -1, (SSC CGL Maths Syllabus)

(b) –2,

(d) 2.

Solution:

(4 – 5) – (13 – 18 + 2).

= -1-(13+2-18).

= -1-(15-18).

= -1-(-3).

= -1+3.

= 2. (SSC CGL Maths Syllabus)

Answer: (d)

5. What is |-26|?

(a) -26,

(b) 26,

(d) 1

Solution:

|-26|

= 26.

Answer: (b)

5. A man has $ 10,000 to invest. He invests $ 4000 at 5 % and $ 3500 at 4 %. In order to have a yearly income of $ 500, he must invest the remainder at:

(a) 6 % , (b) 6.1 %, (c) 6.2 %, (d) 6.3 %, (e) 6.4 % (SSC CGL Maths Syllabus)

Solution:

Income from $ 4000 at 5 % in one year = $ 4000 of 5 %.

= $ 4000 × 5/100.

= $ 4000 × 0.05.

= $ 200.

Income from $ 3500 at 4 % in one year = $ 3500 of 4 %.

= $ 3500 × 4/100.

= $ 3500 × 0.04. (SSC CGL Maths Syllabus)

= $ 140.

Total income from 4000 at 5 % and 3500 at 4 % = $ 200 + $ 140 = $ 340.

Remaining income amount in order to have a yearly income of $ 500 = $ 500 – $ 340. (SSC CGL Maths Syllabus)

= $ 160.

Total invested amount = $ 4000 + $ 3500 = $7500.

Remaining invest amount = $ 10000 – $ 7500 = $ 2500.

We know that, Interest = Principal × Rate × Time

Interest = $ 160,

Principal = $ 2500, (SSC CGL Maths Syllabus)

Rate = r [we need to find the value of r],

Time = 1 year.

160 = 2500 × r × 1.

160 = 2500r

160/2500 = 2500r/2500 [divide both sides by 2500]

0.064 = r

r = 0.064 (SSC CGL Maths Syllabus)

Change it to a percent by moving the decimal to the right two places r = 6.4 %

Therefore, he invested the remaining amount $ 2500 at 6.4 % in order to get $ 500 income every year.

Answer: (e) (SSC CGL Maths Syllabus)

QUESTION6:Find the value of sin2 10 + sin2 20 + sin2 30 + ……. + sin2 80.
(A) 2
(B) 3
(C) 1
(D) 4
Correct Option: D

QUESTION7:Find the value of 16/√3 (Cos50°Cos10°Cos110°Cos60°)
(A) 1
(B) 2
(C) – 1 (SSC CGL Maths Syllabus)
(D) – 2

Correct Option: C

QUESTION8:If the rate of income tax increases by 18%, net income decreases by 2%. What was the rate of income tax?
(A) 10
(B) 20
(C) 15
(D) 12 (SSC CGL Maths Syllabus)

Correct Option: A

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SSC CGL Maths Syllabus (साथ ही मैथ्स के सर्वश्रेष्ठ फ्री नोट्स डाउनलोड करे)

RELATED PDF-

SSC CGL Syllabus 2022:Quantative Aptitude (Mathematics)-

SSC CGL Maths Questions with Solutions PDF

Also Check PDF:-

Important Maths Questions for SSC CGL Exam

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