**Vedic Maths Book PDF Free Download**

**Vedic Maths Book PDF Free Download**

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**Vedic Maths Book CONTENT –**

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### Maths Questions for Competitive Exams with Solutions

1. Mrs. Rodger got a weekly raise of $145. If she gets paid every other week, write an integer describing how the raise will affect her paycheck. (Vedic Maths Book PDF Free Download)

Solution:

Let the 1st paycheck be x (integer).

Mrs. Rodger got a weekly raise of $ 145.

So after completing the 1st week she will get $ (x+145).

Similarly after completing the 2nd week she will get $ (x + 145) + $ 145.

= $ (x + 145 + 145)

= $ (x + 290)

So in this way end of every week her salary will increase by $ 145.

2. The fraction (5x-11)/(2×2 + x – 6) was obtained by adding the two fractions A/(x + 2) and B/(2x – 3). The values of A and B must be, respectively:

(a) 5x, -11, (b) -11, 5x, (c) -1, 3, (d) 3, -1, (e) 5, -11 (Vedic Maths Book PDF Free Download)

Solution:

**Answer: (d)**

3. Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:

(a) broke even, (b) lost 4 cents, (c) gained 4 cents, (d) lost 10 cents, (e) gained 10 cents

Solution:

Selling price of the first pipe = $1.20 (Vedic Maths Book PDF Free Download)

Profit = 20%

Let’s try to find the cost price of the first pipe

CP = Selling price – Profit

CP = 1.20 – 20% of CP

CP = 1.20 – 0.20CP

CP + 0.20CP = 1.20

1.20CP = 1.20

CP = 1.201.20

CP = $ 1

Selling price of the Second pipe = $1.20

Loss = 20%

Let’s try to find the cost price of the second pipe (Vedic Maths Book PDF Free Download)

CP = Selling price + Loss

CP = 1.20 + 20% of CP

CP = 1.20 + 0.20CP

CP – 0.20CP = 1.20

0.80CP = 1.20

CP = 1.200.80

CP = $1.50

Therefore, total cost price of the two pipes = $1.00 + $1.50 = $2.50

And total selling price of the two pipes = $1.20 + $1.20 = $2.40

Loss = $2.50 – $2.40 = $0.10

Therefore, Mr. Jones loss 10 cents. (Vedic Maths Book PDF Free Download)

Answer: (d)

4. The distance light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 100 years is:

(a) 587 × 108 miles, (b) 587 × 1010 miles, (c) 587 × 10-10 miles, (d) 587 × 1012 miles, (e) 587 × 10-12 miles

Solution:

The distance of the light travels in 100 years is:

5,870,000,000,000 × 100 miles.

= 587,000,000,000,000 miles. (Vedic Maths Book PDF Free Download)

= 587 × 1012 miles.

Answer: (d)

5. What is |-26|?

(a) -26,

(b) 26,

(c) 0,

(d) 1

Solution:

|-26|

= 26. (Vedic Maths Book PDF Free Download)

Answer: (b)

6. Multiply: (x – 4)(x + 5)

(a) x2 + 5x – 20,

(b) x2 – 4x – 20,

(c) x2 – x – 20,

(d) x2 + x – 20.

(Vedic Maths Book PDF Free Download)

Solution:

(x – 4)(x + 5).

= x(x + 5) -4(x + 5).

= x2 + 5x – 4x – 20.

= x2 + x – 20.

Answer: (d)

7. Factor: 5×2 – 15x – 20.

(a) 5(x-4)(x+1),

(b) -2(x-4)(x+5), (Vedic Maths Book PDF Free Download)

(c) -5(x+4)(x-1),

(d) 5(x+4)(x+1).

Solution:

5×2 – 15x – 20.

= 5(x2 – 3x – 4).

= 5(x2 – 4x + x – 4).

= 5{x(x – 4) +1(x – 4)}. (Vedic Maths Book PDF Free Download)

= 5(x-4)(x+1).

Answer: (a).

8. If 102y = 25, then 10-y equals:

(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5

Solution:

102y = 25

(10y)2 = 52

10y = 5 (Vedic Maths Book PDF Free Download)

1/10y = 1/5

10-y = 1/5

Answer: (e)

9. The value of x + x(xx) when x = 2 is:

(a) 10, (b) 16, (c) 18, (d) 36, (e) 64

Solution:

x + x(xx)

Put the value of x = 2 in the above expression we get,

2 + 2(22)

= 2 + 2(2 × 2) (Vedic Maths Book PDF Free Download)

= 2 + 2(4)

= 2 + 8

= 10

Answer: (a)

**10. The sum of three numbers is 98. The ratio of the first to the second is ^{2}/_{3}, and the ratio of the second to the third is ^{5}/_{8}. The second number is:**

(a) 15, (b) 20, (c) 30, (d) 32, (e) 33

Solution:

Let the three numbers be x, y and z. (Vedic Maths Book PDF Free Download)

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is ^{2}/_{3}.

x/y = ^{2}/_{3}.

x = ^{2}/_{3} × y.

x = ^{2y}/_{3}.

The ratio of the second to the third is ^{5}/_{8}. (Vedic Maths Book PDF Free Download)

^{y}/_{z} = ^{5}/_{8}.

^{z}/_{y} = ^{8}/_{5}.

z = ^{8}/_{5} × y.

z = ^{8y}/_{5}.

Put the value of x = ^{2y}/_{3} and z = ^{8y}/_{5} in (i).

^{2y}/_{3} + y + ^{8y}/_{5} = 98

^{49y}/_{15} = 98.

49y = 98 × 15. (Vedic Maths Book PDF Free Download)

49y = 1470.

y = ^{1470}/_{49}.

y = 30 .

Therefore, the second number is 30. (Vedic Maths Book PDF Free Download)

**Answer: (c)**

### Maths Questions for Competitive Exams –

1. Which is greater than 4?

(a) 5,

(b) -5, (Vedic Maths Book PDF Free Download)

(c) -1/2,

(d) -25.

Solution:

5 greater than 4.

Answer: (a)

2. Which is the smallest? (Vedic Maths Book PDF Free Download)

(a) -1,

(b) -1/2,

(c) 0,

(d) 3.

Solution:

The smallest number is -1.

Answer: (a)

(Vedic Maths Book PDF Free Download)

3. Combine terms: 12a + 26b -4b – 16a.

(a) 4a + 22b,

(b) -28a + 30b,

(c) -4a + 22b,

(d) 28a + 30b.

(Vedic Maths Book PDF Free Download)

Solution:

12a + 26b -4b – 16a.

= 12a – 16a + 26b – 4b.

= -4a + 22b.

Answer: (c)

4. Simplify: (4 – 5) – (13 – 18 + 2). (Vedic Maths Book PDF Free Download)

(a) -1,

(b) –2,

(c) 1,

(d) 2.

Solution:

(4 – 5) – (13 – 18 + 2).

= -1-(13+2-18).

= -1-(15-18).

= -1-(-3).

= -1+3.

= 2. (Vedic Maths Book PDF Free Download)

Answer: (d)

5. What is |-26|?

(a) -26,

(b) 26,

(c) 0, (Vedic Maths Book PDF Free Download)

(d) 1

Solution:

|-26|

= 26.

Answer: (b)

5. A man has $ 10,000 to invest. He invests $ 4000 at 5 % and $ 3500 at 4 %. In order to have a yearly income of $ 500, he must invest the remainder at:

(a) 6 % , (b) 6.1 %, (c) 6.2 %, (d) 6.3 %, (e) 6.4 % (Vedic Maths Book PDF Free Download)

Solution:

Income from $ 4000 at 5 % in one year = $ 4000 of 5 %.

= $ 4000 × 5/100.

= $ 4000 × 0.05.

= $ 200.

Income from $ 3500 at 4 % in one year = $ 3500 of 4 %.

= $ 3500 × 4/100.

= $ 3500 × 0.04. (Vedic Maths Book PDF Free Download)

= $ 140.

Total income from 4000 at 5 % and 3500 at 4 % = $ 200 + $ 140 = $ 340.

Remaining income amount in order to have a yearly income of $ 500 = $ 500 – $ 340.

= $ 160.

Total invested amount = $ 4000 + $ 3500 = $7500.

Remaining invest amount = $ 10000 – $ 7500 = $ 2500.

We know that, Interest = Principal × Rate × Time

Interest = $ 160,

Principal = $ 2500, (Vedic Maths Book PDF Free Download)

Rate = r [we need to find the value of r],

Time = 1 year.

160 = 2500 × r × 1.

160 = 2500r

160/2500 = 2500r/2500 [divide both sides by 2500]

0.064 = r

r = 0.064 (Vedic Maths Book PDF Free Download)

Change it to a percent by moving the decimal to the right two places r = 6.4 %

Therefore, he invested the remaining amount $ 2500 at 6.4 % in order to get $ 500 income every year.

Answer: (e) (Vedic Maths Book PDF Free Download)

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6. Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:

(a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much

Solution: (Vedic Maths Book PDF Free Download)

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

We know that

Speed = Distance/Time.

Or, Time = Distance/Speed.

So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.

And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr. (Vedic Maths Book PDF Free Download)

So we can clearly see that his new time compared with the old time was: twice as much.

Answer: (b)

7. If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is:

(a) -10.0, (b) -0.5, (c) -0.4, (d) -0.2, (e) 10.0

Solution:

(0.2)x = 2.

Taking log on both sides

log (0.2)x = log 2. (Vedic Maths Book PDF Free Download)

x log (0.2) = 0.3010, [since log 2 = 0.3010].

x log (2/10) = 0.3010.

x [log 2 – log 10] = 0.3010.

x [log 2 – 1] = 0.3010,[since log 10=1].

x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].

x[-0.699] = 0.3010.

x = 0.3010/-0.699.

x = -0.4306…. (Vedic Maths Book PDF Free Download)

x = -0.4 (nearest tenth)

Answer: (c)

6. Multiply: (x – 4)(x + 5)

(a) x2 + 5x – 20,

(b) x2 – 4x – 20,

(c) x2 – x – 20,

(d) x2 + x – 20. (Vedic Maths Book PDF Free Download)

Solution:

(x – 4)(x + 5).

= x(x + 5) -4(x + 5).

= x2 + 5x – 4x – 20.

= x2 + x – 20.

Answer: (d)

(Vedic Maths Book PDF Free Download)

7. Factor: 5×2 – 15x – 20.

(a) 5(x-4)(x+1),

(b) -2(x-4)(x+5),

(c) -5(x+4)(x-1),

(d) 5(x+4)(x+1).

Solution:

5×2 – 15x – 20.

= 5(x2 – 3x – 4).

= 5(x2 – 4x + x – 4). (Vedic Maths Book PDF Free Download)

= 5{x(x – 4) +1(x – 4)}.

= 5(x-4)(x+1).

Answer: (a).

8. Factor: 3y(x – 3) -2(x – 3).

(a) (x – 3)(x – 3),

(b) (x – 3)2,

(c) (x – 3)(3y – 2),

(d) 3y(x – 3).

Solution: (Vedic Maths Book PDF Free Download)

3y(x – 3) -2(x – 3).

= (x – 3)(3y – 2).

Answer: (c).

9. Solve for x: 2x – y = (3/4)x + 6.

(a) (y + 6)/5,

(b) 4(y + 6)/5,

(c) (y + 6), (Vedic Maths Book PDF Free Download)

(d) 4(y – 6)/5.

Solution:

2x – y = (3/4)x + 6.

or, 2x – (3/4)x = y + 6.

or, (8x -3x)/4 = y + 6.

or, 5x/4 = y + 6.

or, 5x = 4(y + 6). (Vedic Maths Book PDF Free Download)

or, 5x = 4y + 24.

or, x = (4y + 24)/5.

Therefore, x = 4(y + 6)/5.

Answer: (b).

10. Simplify:(4×2 – 2x) – (-5×2 – 8x).

Solution:

(4×2 – 2x) – (-5×2 – 8x)

= 4×2 – 2x + 5×2 + 8x.

= 4×2 + 5×2 – 2x + 8x. (Vedic Maths Book PDF Free Download)

= 9×2 + 6x.

= 3x(3x + 2).

Answer: 3x(3x + 2)

11. Find the value of 3 + 2 • (8 – 3)

(a) 25,

(b) 13, (Vedic Maths Book PDF Free Download)

(c) 17,

(d) 24,

(e) 15.

Solution:

3 + 2 • (8 – 3)

= 3 + 2 (5)

= 3 + 2 × 5

= 3 + 10

= 13 (Vedic Maths Book PDF Free Download)

Answer: (d)

12. Rice weighing 33/4 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each?

Solution:

33/4 ÷ 4 pounds.

= (4 × 3 + 3)/4 ÷ 4 pounds.

= 15/4 ÷ 4 pounds. (Vedic Maths Book PDF Free Download)

= 15/4 × 1/4 pounds.

= 15/16 pounds.

Now we know that, 1 pound = 16 ounces.

Therefore, 15/16 pounds = 15/16 × 16 ounces.

= 15 ounces.

Answer: 15 ounces.

13. Factor: 16w3 – u4w3 (Vedic Maths Book PDF Free Download)

Solution:

16w3 – u4w3.

= w3(16 – u4).

= w3(42 – ((u2)2).

= w3(4 + u2)(4 – u2).

= w3(4 + u2)(22 – u2).

= w3(4 + u2)(2 + u)(2 – u).

Answer: w3(4 + u2)(2 + u)(2 – u).

(Vedic Maths Book PDF Free Download)

14. Factor: 3x4y3 – 48y3.

Solution:

3x4y3– 48y3.

= 3y3(x4 – 16).

= 3y3[(x2)2 – 42].

= 3y3(x2 + 4)(x2 – 4).

= 3y3(x2 + 4)(x2 – 22).

= 3y3(x2 + 4)(x + 2)(x -2).

Answer: 3y3(x2 + 4)(x + 2)(x -2)

(Vedic Maths Book PDF Free Download)

15. What is the radius of a circle that has a circumference of 3.14 meters?

Solution:

Circumference of a circle = 2πr.

Given, circumference = 3.14 meters.

Therefore,

2πr = Circumference of a circle

or, 2πr = 3.14.

or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].

or, 6.28r = 3.14. (Vedic Maths Book PDF Free Download)

or, r = 3.14/6.28.

or, r = 0.5.

Answer: 0.5 meter.

16. When (6767 +67) is divided by 68, the remainder is-

a. 1

b. 63

c. 66

d. 67

Hide Answer

(Vedic Maths Book PDF Free Download)

Ans: (6767+ 67) = 67(6766 + 166)

As 66 is an even number

We know 6766 is an even number

We know (6766 + 1) is perfectly divisible by (67 + 1)

i.e. 68

We know The remainder = 66

17. In a division sum, the divisor is 4 times the quotient and twice the remainder. If a and b are respectively the divisor and the dividend then-

a. 4b-a2 /a =3

b. 4b-2a /a2 =2

c. (a+1)2 = 4b (Vedic Maths Book PDF Free Download)

d. A(a+2)/b = 4

Hide Answer

Ans : As divisor is a, and dividend is b.

We know Quotient = a/4

And Remainder = a/2

We know b = a * a/4 + a/2

We know 4b = a2 + 2a

We know a(a+2)/b = 4

(Vedic Maths Book PDF Free Download)

18. If 738 A6A is divisible by 11, then the value of A is-

a. 6

b. 3

c. 9

d. 1

Hide Answer

Ans : As 738A6 A is divisible by 11.

We know A + A + 3 = 6 + 8 + 7

We know A = 9

(Vedic Maths Book PDF Free Download)

19. The east positive integer that should be subtracted from 3011 * 3012 so that the difference is perfect square is-

a. 3009

b. 3010

c. 3011

d. 3012

Hide Answer

Ans : We know that 3011 * 3012 = 3011 (3011 + 1)

= (3011)2 + 3011 (Vedic Maths Book PDF Free Download)

We know Required least number = 3011

20. P, Q, R are employed to do a work for Rs. 5750. P and Q together finished 19/23 of work and Q and R together finished 8/23 of work. Wage of Q, in rupees, is-

a. 2850

b. 3750

c. 2750

d. 1000

Hide Answer

Ans : Work done by Q = 19/23 + 8/23 – 1

4/23 (Vedic Maths Book PDF Free Download)

We know Wage of Q = 4/23 * 5750

= Rs. 1000

21. A can do a piece of work in 24 day, B in 32 days and C in 64 days. All begin to do it together, but A leaves after 6 days and B leaves 6 days before the completion of the work. How many days did the work last?

a. 15

b. 20

c. 18 (Vedic Maths Book PDF Free Download)

d. 30

Hide Answer

Ans : Work done by A = 6/24 = ¼

Work done by B = (x-6)/32

(where x is no. of days in which work is competed)

We know that ¼ + x – 6/32 + x/64 = 1

We know 16 + 24 – 12 + x /64 = 1

We know 3x + 4 = 64

We know x = 60/3 = 20 days

22. The product of 2 numbers is 1575 and their quotient is 9/7. Then the sum of the numbers is –

a. 74 (Vedic Maths Book PDF Free Download)

b. 78

c. 80

d. 90

Hide Answer

Ans : Let the numbers be x and y .

We know xy = 1575

And x/y = 9/7

We know xy/x/y = 1575/9/7 (Vedic Maths Book PDF Free Download)

We know y2 = 1225

We know y = 35 and x = 45

We know The sum of the numbers = 45+35

= 80

23. The value of (81)3.6 * (9)2.7/ (81)4.2 * (3) is __

a. 3

b. 6 (Vedic Maths Book PDF Free Download)

c. 9

d. 8.2

Hide Answer

Ans : (81)3.6 * (9)2.7/(81)4.2 * (3) = (3)14.4 * (3)5.4/(3)16.8 * (3)

= 314.4+5.4-16.8-1

= 32

= 9 (Vedic Maths Book PDF Free Download)

24. √6+√6+√6+… is equal to –

a. 2

b. 5

c. 4

d. 3

Ans : Let √6+√6+√6+…. be x.

We know x =√6+x

We know x2 = 6+x

We know x2 – x – 6 = 0

We know (x-3) (x+2) = 0

We know x = 3 (Vedic Maths Book PDF Free Download)

25. The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is –

a. 24

b. 32

c. 40

d. 28

Hide Answer

(Vedic Maths Book PDF Free Download)

Ans : Let the consecutive odd numbers be x and (x+2)

We know that x2 + (x + 2)2 = 394

We know x2 + x2 + 4x + 4 = 394

We know 2 x2 +4x – 390 = 0

We know x2 + 2x – 195 = 0

We know (x +15) (x-13) = 0

We know x = 13

We know Required sum = 13 +15 =28 (Vedic Maths Book PDF Free Download)

**TEST YOURSELF | क्या आप यह प्रश्न कर सकते हैं | Unsolved Questions:**

**1.** A sports field is 300 feet long. Write a formula that gives the length of x sports fields in feet. Then use this formula to determine the number of sports fields in 720 feet.

**2.** A recipe calls for 2 1/2 cups and I want to make 1 1/2 recipes. How many cups do I need?

**3.** Fahrenheit temperature F is a linear function of Celsius temperature C. The ordered pair (0, 32) is an ordered pair of this function because 0°C is equivalent to 32°F, the freezing point of water. The ordered pair (100, 212) is also an ordered pair of this function because 100°C is equivalent to 212° F, the boiling point of water. (Vedic Maths Book PDF Free Download)

**4.** Mario answered 30% of the questions correctly. The test contained a total of 80 questions. How many questions did Mario answer correctly?

**Vedic Maths Book PDF Free Download:-**

**⇓****⇓****⇓****⇓**

**CLICK HERE TO DOWNLOAD THE PDF>>**

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